nilai dari sin 1999°
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Jawab:
Penjelasan dengan langkah-langkah:
sin (n × 360° + α) = sin α
cos (n × 360° + α) = cos α
tan (n × 360° + α) = tan α
Kita cari nilai n sehingga n × 360° mendekati 1.470°
Jika n = 1 => 1 × 360° = 360°
Jika n = 2 => 2 × 360° = 720°
Jika n = 3 => 3 × 360° = 1.080°
Jika n = 4 => 4 × 360° = 1.440°
==> sudah mendekati 1.470°
Jadi
sin 1.470°
= sin (1.440° + 30°)
= sin (4 × 360° + 30°)
= sin 30°
= 1/2
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